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Proof lnexy = xy = lnex lney = ln(ex ·ey) Since lnx is onetoone, then exy = ex ·ey 1 = e0 = ex(−x) = ex ·e−x ⇒ e−x = 1 ex ex−y = ex(−y) = ex ·e−y = ex · 1 ey ex ey • For r = m ∈ N, emx = e z }m { x···x = z }m { ex ···ex = (ex)m • For r = 1 n, n ∈ N and n 6= 0, ex = e n n x = e 1 nx n ⇒ e n x = (ex) 1 • For r rational, let r = m n, m, n ∈ NQ@ Q@ Q@ Q@ Q@ Q@ Q@ Q@ Q@ Q@ Q@ JÒ4ReãÖš— 5 }ÌqÏ Ô"«TH™õ¥ æ†íJ€³( H1h çœc*·cÛ½24Ä$7s@Ç Ê"XÙ%ïÏc'9GÈúU&"¢£©ä‚¦´!E v E H A s Z b g A Ód C p i A ʍH ̊ ̃z y W ł B R u ̃V b _ A A X x X g E @ 戵 Ă ܂ B DAIKI n ƈȗ 30 N A i v p H A s Z b g ̕i L x ł B DAIKI RUBIS r X H ƃs Z b g ̑ A 㗝 X ł B 07 N A X x X g o E @ Abatement Technologies 㗝 X Ƃ ď i 戵 J n ܂ B Jyryd Papjujqm ©í¢¢ sAm CXg È'P '«û
